什么是关键的折射角的彩虹出现,到最近的学位?PositronWildhawk Britgirl divphygamer(What is the critical angle of refraction at which a rainbow appears, to the nearest degree? PositronWildhawk Britgirl divphygamer)——欧美十大问题可能是对生命、宇宙和一切事物的臭名昭著的终极问题

什么是关键的折射角的彩虹出现,到最近的学位?PositronWildhawk Britgirl divphygamer(What is the critical angle of refraction at which a rainbow appears, to the nearest degree?PositronWildhawkBritgirldivphygamer)——欧美十大问题可能是对生命、宇宙和一切事物的臭名昭著的终极问题在《欧美十大问题可能是对生...

什么是关键的折射角的彩虹出现,到最近的学位?PositronWildhawk Britgirl divphygamer(What is the critical angle of refraction at which a rainbow appears, to the nearest degree? PositronWildhawk Britgirl divphygamer)——欧美十大问题可能是对生命、宇宙和一切事物的臭名昭著的终极问题在欧美十大问题可能是对生命宇宙和一切事物的臭名昭著的终极问题中排名第2名。

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只能有一个答案。- PositronWildhawk

There can only be one answer to this. - PositronWildhawk

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我不知道. .四十什么. . ?——Britgirl

I don't know... Forty something... ? - Britgirl

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答案是正确的。

The answer is correct.

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42.在数学和科学。- divphygamer非常重要

42.Really important in maths and science. - divphygamer

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激光束在空气中是事件在乙醇在37.0度的入射角。所以如果你想找到折射角:N1 sin1 O1 = n2罪O2O2 = sin-1n1罪O1 + 2 = sin-1[1.00][罪37.0度]。- letdot52 ++ 1.36 = 26.3度

Well, A laser beam in the air is incident upon ethanol at an angle of incidence of 37.0degrees. So if you want to find the angle of refraction then:N1 sin1 O1 = n2 sin O2O2 = sin-1(n1 sin O1/n2)= sin-1([1.00][sin 37.0degrees]/1.36)=26.3degrees. - letdot52

发表于 2020-12-03 07:01
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分类：教育

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